Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

Hi Everyone,
Post your solutions to the Nov 28 In-Class exercises to this thread.
Best,
Chris
Hi Everyone, Post your solutions to the Nov 28 In-Class exercises to this thread. Best, Chris
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

[0 100]
  • d=1: [0 50 100] the optimal is 0
  • d=2: [0 25 50] the optimal is 25;
  • here we divide the range by (k+1)
  • d=3: [12.5 25 37.5] the optimal is also 25

Last Edited: 29/11/2017
[0 100] * d=1: [0 50 100] the optimal is 0 * d=2: [0 25 50] the optimal is 25; * here we divide the range by (k+1) * d=3: [12.5 25 37.5] the optimal is also 25
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

  • l = 100
  • h1 = [0, 50, 100]
  • h2 = [16, 33, 50]
  • h3 = [16, 24.5, 33]
* l = 100 * h1 = [0, 50, 100] * h2 = [16, 33, 50] * h3 = [16, 24.5, 33]
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017


Kunal Deshmukh
d = 0   possible values for lambda = 0    50     100
d = 1   possible values for lambda = 0    25     50
d = 2   possible values for lambda = 12   25     37
hence selected value = 25 

 
<nowiki> Kunal Deshmukh d = 0 possible values for lambda = 0 50 100 d = 1 possible values for lambda = 0 25 50 d = 2 possible values for lambda = 12 25 37 hence selected value = 25 </nowiki>
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

range = {0..100} k = 3 , d = 3 (we stop when d = 3) d = 1 : [0 50 100] the optimal is 50 d = 2: [0 25 50] the optimal is 25 because lamda = 21 d = 3: [12 25 37] The optimal is still 25
range = {0..100} k = 3 , d = 3 (we stop when d = 3) d = 1 : [0 50 100] the optimal is 50 d = 2: [0 25 50] the optimal is 25 because lamda = 21 d = 3: [12 25 37] The optimal is still 25
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

{0, 50, 100} d = 1 {0, 25, 50} d = 2 {12.5, 25, 37.5} d =3
{0, 50, 100} d = 1 {0, 25, 50} d = 2 {12.5, 25, 37.5} d =3
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

n= 100 k=3 d=3 lamda=21
(0,50,100} 0 is chosen
{0,25,50} 25 is chosen
{12.5,25,37.5}
25 is chosen at depth 3

Last Edited: 29/11/2017
n= 100 k=3 d=3 lamda=21 (0,50,100} 0 is chosen {0,25,50} 25 is chosen {12.5,25,37.5} 25 is chosen at depth 3
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

Depth 0: [0, 50, 100], Depth 1: [0, 25, 50], Depth 2: [13, 25, 37]

Last Edited: 29/11/2017
Depth 0: [0, 50, 100], Depth 1: [0, 25, 50], Depth 2: [13, 25, 37]
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

Name - Krishna Vojjila for depth 0, [0,50,100] is taken. 0 is chosen for depth 1, [0,25,50] is taken, 25 is chosen for depth 3, [12.5,25,37.5], 25 is chosen
Name - Krishna Vojjila for depth 0, [0,50,100] is taken. 0 is chosen for depth 1, [0,25,50] is taken, 25 is chosen for depth 3, [12.5,25,37.5], 25 is chosen
 

-- Nov 28 In-Class Exercise. - 29/11/2017 CS 256 Fall 2017

d = 3, k = 3, n = 100 when d = 0, possible `lambda` values = {0, 50, 100} when d = 1, possible `lambda` values = {0, 25, 50} when d = 2 possible `lambda` values = {12, 25, 37} value 25 is taken.

Last Edited: 29/11/2017
d = 3, k = 3, n = 100 when d = 0, possible `lambda` values = {0, 50, 100} when d = 1, possible `lambda` values = {0, 25, 50} when d = 2 possible `lambda` values = {12, 25, 37} value 25 is taken.
 
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