Hi Everyone,

Post your solutions to the Nov 28 In-Class exercises to this thread.

Best,

Chris

Hi Everyone,
Post your solutions to the Nov 28 In-Class exercises to this thread.
Best,
Chris

[0 100]

- d=1: [0 50 100] the optimal is 0
- d=2: [0 25 50] the optimal is 25;
- here we divide the range by (k+1)
- d=3: [12.5 25 37.5] the optimal is also 25

[0 100]
* d=1: [0 50 100] the optimal is 0
* d=2: [0 25 50] the optimal is 25;
* here we divide the range by (k+1)
* d=3: [12.5 25 37.5] the optimal is also 25

- l = 100
- h1 = [0, 50, 100]
- h2 = [16, 33, 50]
- h3 = [16, 24.5, 33]

* l = 100
* h1 = [0, 50, 100]
* h2 = [16, 33, 50]
* h3 = [16, 24.5, 33]

Kunal Deshmukh d = 0 possible values for lambda = 0 50 100 d = 1 possible values for lambda = 0 25 50 d = 2 possible values for lambda = 12 25 37 hence selected value = 25

<nowiki>
Kunal Deshmukh
d = 0 possible values for lambda = 0 50 100
d = 1 possible values for lambda = 0 25 50
d = 2 possible values for lambda = 12 25 37
hence selected value = 25
</nowiki>

range = {0..100}
k = 3 , d = 3 (we stop when d = 3)
d = 1 : [0 50 100] the optimal is 50
d = 2: [0 25 50] the optimal is 25 because lamda = 21
d = 3: [12 25 37] The optimal is still 25

range = {0..100}
k = 3 , d = 3 (we stop when d = 3)
d = 1 : [0 50 100] the optimal is 50
d = 2: [0 25 50] the optimal is 25 because lamda = 21
d = 3: [12 25 37] The optimal is still 25

{0, 50, 100} d = 1
{0, 25, 50} d = 2
{12.5, 25, 37.5} d =3

{0, 50, 100} d = 1
{0, 25, 50} d = 2
{12.5, 25, 37.5} d =3

n= 100
k=3
d=3
lamda=21

(0,50,100}
0 is chosen

{0,25,50}
25 is chosen

{12.5,25,37.5}

25 is chosen at depth 3

n= 100
k=3
d=3
lamda=21
(0,50,100}
0 is chosen
{0,25,50}
25 is chosen
{12.5,25,37.5}
25 is chosen at depth 3

Depth 0: [0, 50, 100],
Depth 1: [0, 25, 50],
Depth 2: [13, 25, 37]

Depth 0: [0, 50, 100],
Depth 1: [0, 25, 50],
Depth 2: [13, 25, 37]

Name - Krishna Vojjila
for depth 0, [0,50,100] is taken. 0 is chosen
for depth 1, [0,25,50] is taken, 25 is chosen
for depth 3, [12.5,25,37.5], 25 is chosen

Name - Krishna Vojjila
for depth 0, [0,50,100] is taken. 0 is chosen
for depth 1, [0,25,50] is taken, 25 is chosen
for depth 3, [12.5,25,37.5], 25 is chosen

d = 3, k = 3, n = 100
when d = 0, possible `lambda` values = {0, 50, 100}
when d = 1, possible `lambda` values = {0, 25, 50}
when d = 2 possible `lambda` values = {12, 25, 37}
value 25 is taken.

d = 3, k = 3, n = 100
when d = 0, possible `lambda` values = {0, 50, 100}
when d = 1, possible `lambda` values = {0, 25, 50}
when d = 2 possible `lambda` values = {12, 25, 37}
value 25 is taken.