2017-11-29
Nov 28 In-Class Exercise.
Hi Everyone,
Post your solutions to the Nov 28 In-Class exercises to this thread.
Best,
Chris
Hi Everyone,
Post your solutions to the Nov 28 In-Class exercises to this thread.
Best,
Chris
[0 100]
- d=1: [0 50 100] the optimal is 0
- d=2: [0 25 50] the optimal is 25;
- here we divide the range by (k+1)
- d=3: [12.5 25 37.5] the optimal is also 25
[0 100]
* d=1: [0 50 100] the optimal is 0
* d=2: [0 25 50] the optimal is 25;
* here we divide the range by (k+1)
* d=3: [12.5 25 37.5] the optimal is also 25
- l = 100
- h1 = [0, 50, 100]
- h2 = [16, 33, 50]
- h3 = [16, 24.5, 33]
* l = 100
* h1 = [0, 50, 100]
* h2 = [16, 33, 50]
* h3 = [16, 24.5, 33]
Kunal Deshmukh
d = 0 possible values for lambda = 0 50 100
d = 1 possible values for lambda = 0 25 50
d = 2 possible values for lambda = 12 25 37
hence selected value = 25
<nowiki>
Kunal Deshmukh
d = 0 possible values for lambda = 0 50 100
d = 1 possible values for lambda = 0 25 50
d = 2 possible values for lambda = 12 25 37
hence selected value = 25
</nowiki>
range = {0..100}
k = 3 , d = 3 (we stop when d = 3)
d = 1 : [0 50 100] the optimal is 50
d = 2: [0 25 50] the optimal is 25 because lamda = 21
d = 3: [12 25 37] The optimal is still 25
range = {0..100}
k = 3 , d = 3 (we stop when d = 3)
d = 1 : [0 50 100] the optimal is 50
d = 2: [0 25 50] the optimal is 25 because lamda = 21
d = 3: [12 25 37] The optimal is still 25
{0, 50, 100} d = 1
{0, 25, 50} d = 2
{12.5, 25, 37.5} d =3
{0, 50, 100} d = 1
{0, 25, 50} d = 2
{12.5, 25, 37.5} d =3
n= 100
k=3
d=3
lamda=21
(0,50,100}
0 is chosen
{0,25,50}
25 is chosen
{12.5,25,37.5}
25 is chosen at depth 3
(Edited: 2017-11-29) n= 100
k=3
d=3
lamda=21
(0,50,100}
0 is chosen
{0,25,50}
25 is chosen
{12.5,25,37.5}
25 is chosen at depth 3
Depth 0: [0, 50, 100],
Depth 1: [0, 25, 50],
Depth 2: [13, 25, 37]
(Edited: 2017-11-29) Depth 0: [0, 50, 100],
Depth 1: [0, 25, 50],
Depth 2: [13, 25, 37]
Name - Krishna Vojjila
for depth 0, [0,50,100] is taken. 0 is chosen
for depth 1, [0,25,50] is taken, 25 is chosen
for depth 3, [12.5,25,37.5], 25 is chosen
Name - Krishna Vojjila
for depth 0, [0,50,100] is taken. 0 is chosen
for depth 1, [0,25,50] is taken, 25 is chosen
for depth 3, [12.5,25,37.5], 25 is chosen
d = 3, k = 3, n = 100
when d = 0, possible `lambda` values = {0, 50, 100}
when d = 1, possible `lambda` values = {0, 25, 50}
when d = 2 possible `lambda` values = {12, 25, 37}
value 25 is taken.
(Edited: 2017-11-29) d = 3, k = 3, n = 100
when d = 0, possible @BT@lambda@BT@ values = {0, 50, 100}
when d = 1, possible @BT@lambda@BT@ values = {0, 25, 50}
when d = 2 possible @BT@lambda@BT@ values = {12, 25, 37}
value 25 is taken.
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