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-- Nov 28 In-Class Exercise

Assuming a line plot for n = 12 between n = 8 and n = 16, When m = 50, Approximating k value it comes around 14. So, answer is k = 14

-- Nov 28 In-Class Exercise

Based on the given graph, Line for n=12, would require, in between n=8 and n=16. After taking mean of both of values of k for m=50, I got k=12.

-- Nov 28 In-Class Exercise

Based on the plot given in the lecture notes, n=12 should be between n=8 and n=16. With m=50, the value of k would be around 14

-- Nov 28 In-Class Exercise

From the graph given in the previous slide, n=12 will fall between the graph of n=8 and n=16, so the number of documents should each machine compute would be either 13 or 14.

-- Nov 28 In-Class Exercise

Based on the chart provided in the slides, each machine should return about 13 documents. At m = 50, n=8 returns ~15 documents. At m = 50, n=16 returns ~10 documents. Because n=12 is halfway between n = 8 and n = 16, we can assume that ~ (10+15 / 2) = 13.

-- Nov 28 In-Class Exercise

The line would lie between n = 8 and n = 16.
As for n = 16, k is 10
for n = 8, k is 15
So from this we can say that for n = 12, the k value can be 12 or 13.

(Edited: 2018-12-03)

<pre> The line would lie between n = 8 and n = 16. As for n = 16, k is 10 for n = 8, k is 15 So from this we can say that for n = 12, the k value can be 12 or 13.</pre>