Professor I am bit confused with the layout given with this question. Are we to go blindly as a computer when solving for squares 1,3 and 3,1? Because since sqaure 2,2 is not a pit then 1,3 and 3,1 are pits 100% pits, albeit i am not sure how to express that with the probability model that we were shown. Also the fact the square 2,2 is B,S means one square is a pit and one square is a wumpus, can we safely assume that a wumpus will not be in a pit? But if we deduct all of this logically then the agent will die no matter what. I am a bit lost as well as how to incorporate a wumpus in our model. Do we only calculate him when working with squares 2,3 and 3,2? and not in other squares eg: P13 = (.2(x),.8(y) (not using the wumpus in any square) P13 = (.2(x),.0625(y),.7375(z)) Its hard to explain just by text so if there is anything i didnt explain please let me know to clarify further.

-- Problem 2 HW 5

Hey Enrique, Pits and Wumpuses can be in the same room. For 1,3 and 3,1, you should derive using probability what would be true using just a logical argument. You should justify how a program could decide that we wouldn't need to consider the Wumpus for 1,3 and 3,1, if you don't consider the wumpus for those squares. Best, Chris