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Nov 6 In-Class Exercise Thread .

Post your solutions to the Nov 6 In-Class Exercise to this thread.

Best,

Chris

Post your solutions to the Nov 6 In-Class Exercise to this thread. Best, Chris

-- Nov 6 In-Class Exercise Thread

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-- Nov 6 In-Class Exercise Thread

For document "Popeye's Chicken Sandwich" :-

f(t,d) = log(1+3/3)= 1 For term Popeye's, (log(1+56/100000) + log(1+100000/56))/2 = 5.4 approx log(1+56/100000) = 0 (approx) For term Chicken, (log(1+501/100000) + log(1+100000/501))/2 = 3.824 approx log(1+501/100000) = 0 (approx)

DFR of this document = 9.224

For document "Popeye's Chicken Sandwich Deal" :-

f(t,d) = log(1+3/4)= 0.8 For term Popeye's, (log(1+56/100000) + 0.8*log(1+100000/56))/1.8 = 4.8 approx log(1+56/100000) = 0 (approx)

For term Chicken, (log(1+501/100000) + 0.8*log(1+100000/501))/1.8 = 3.399 approx log(1+501/100000) = 0 (approx)

DFR of this document = 8.19 approx

For document "Popeye's Chicken Sandwich" :- f(t,d) = log(1+3/3)= 1 For term Popeye's, (log(1+56/100000) + log(1+100000/56))/2 = 5.4 approx log(1+56/100000) = 0 (approx) For term Chicken, (log(1+501/100000) + log(1+100000/501))/2 = 3.824 approx log(1+501/100000) = 0 (approx) DFR of this document = 9.224 For document "Popeye's Chicken Sandwich Deal" :- f(t,d) = log(1+3/4)= 0.8 For term Popeye's, (log(1+56/100000) + 0.8*log(1+100000/56))/1.8 = 4.8 approx log(1+56/100000) = 0 (approx) For term Chicken, (log(1+501/100000) + 0.8*log(1+100000/501))/1.8 = 3.399 approx log(1+501/100000) = 0 (approx) DFR of this document = 8.19 approx

-- Nov 6 In-Class Exercise Thread

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-- Nov 6 In-Class Exercise Thread

(Edited: 2019-11-06)

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-- Nov 6 In-Class Exercise Thread

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-- Nov 6 In-Class Exercise Thread

(Edited: 2019-11-06)

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-- Nov 6 In-Class Exercise Thread

(Edited: 2019-11-06)

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-- Nov 6 In-Class Exercise Thread

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-- Nov 6 In-Class Exercise Thread

Docs first - Popeye's Chicken Sandwich = log(1+56/10^5)/2 + log(1+10^5/56)/2 + log(1+501/10^5)/2 + log(1+10^5/501)/2=[0.00081+10.8+0.0072+7.65]/2= 9.23

second - Popeye's Chicken Sandwich Deal = log( 1 + 56/10^5) + log(1.75)log(1+10^5/56) / (1+log(1.75)) + log( 1 + 501/10^5) + log(1.75)log(1+10^5/501) / (1+log(1.75)) = 4.82+3.4 = 8.22

(Edited: 2019-11-09)

Docs first - Popeye's Chicken Sandwich = log(1+56/10^5)/2 + log(1+10^5/56)/2 + log(1+501/10^5)/2 + log(1+10^5/501)/2=[0.00081+10.8+0.0072+7.65]/2= 9.23 second - Popeye's Chicken Sandwich Deal = log( 1 + 56/10^5) + log(1.75)log(1+10^5/56) / (1+log(1.75)) + log( 1 + 501/10^5) + log(1.75)log(1+10^5/501) / (1+log(1.75)) = 4.82+3.4 = 8.22