2020-01-29

Jan 29 In-Class Exercise.

Howdy Everyone,
Please post your solution to the Jan 29 In-Class Exercise to this thread.
Best,
Chris
Howdy Everyone, Please post your solution to the Jan 29 In-Class Exercise to this thread. Best, Chris

-- Jan 29 In-Class Exercise
3 platters = 6 surfaces
2.6 TB/200,000 = `1.3 times 10^7` = 13MB
(Edited: 2020-02-01)
3 platters = 6 surfaces 2.6 TB/200,000 = @BT@1.3 times 10^7@BT@ = 13MB

-- Jan 29 In-Class Exercise
Resource Description for 0BBEACCD-C566-4EE5-96F0-81A536279F63.jpeg
((resource:0BBEACCD-C566-4EE5-96F0-81A536279F63.jpeg|Resource Description for 0BBEACCD-C566-4EE5-96F0-81A536279F63.jpeg))

-- Jan 29 In-Class Exercise
16TB / (6 * 200,000tracks) = (16 * 10^12B) / (6 * 2 * 10^5 tracks) = 13.3MB
(Edited: 2020-01-29)
16TB / (6 * 200,000tracks) = (16 * 10^12B) / (6 * 2 * 10^5 tracks) = 13.3MB

-- Jan 29 In-Class Exercise
 3 Platters = 6 surfaces. 16TB / 6 surfaces = 2.666 * 10^12 bytes. Bytes per track = 2.666 * 10^12 bytes / 2 * 10^5 = 1.333 * 10^7 bytes = 13MB
(Edited: 2020-01-29)
3 Platters = 6 surfaces. 16TB / 6 surfaces = 2.666 * 10^12 bytes. Bytes per track = 2.666 * 10^12 bytes / 2 * 10^5 = 1.333 * 10^7 bytes = 13MB

-- Jan 29 In-Class Exercise
 3 platters -> 6 surfaces
 16TB / 6 surfaces = 2.67 TB
 (2.67 * 10^12) / (2 * 10^5) = 1.33 * 10^7 = 13.3 MB
3 platters -> 6 surfaces 16TB / 6 surfaces = 2.67 TB (2.67 * 10^12) / (2 * 10^5) = 1.33 * 10^7 = 13.3 MB
2020-02-02

-- Jan 29 In-Class Exercise
((resource:IMG_8009.HEIC|Resource Description for IMG_8009.HEIC))

-- Jan 29 In-Class Exercise
Resource Description for assignment 1.jpg
((resource:assignment 1.jpg|Resource Description for assignment 1.jpg))

-- Jan 29 In-Class Exercise
3 platters -> 6 surfaces
Number of bytes/surface = 16TB / 6 surfaces = 2.67 TB
Number of bytes/track = 2.67TB / 200,000 tracks = (2.67*10^12 B) / (2*10^5 tracks) = 13.35 MB
(Edited: 2020-02-03)
3 platters -> 6 surfaces Number of bytes/surface = 16TB / 6 surfaces = 2.67 TB Number of bytes/track = 2.67TB / 200,000 tracks = (2.67*10^12 B) / (2*10^5 tracks) = 13.35 MB

-- Jan 29 In-Class Exercise
We have 3 platters -> 6 surfaces. We have 16TB Capacity in total. Per surface we have 8/3 TB.
We have 200,000 tracks per surface. Therefore, we have (8/3) / (200,000) TB/track Which is 13.33MB per track!
We have 3 platters -> 6 surfaces. We have 16TB Capacity in total. Per surface we have 8/3 TB. We have 200,000 tracks per surface. Therefore, we have (8/3) / (200,000) TB/track Which is 13.33MB per track!
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