2021-11-09
Nov 10 In-Class Exercise Thread .
Please post your solutions to the Nov 10 In-Class Exercise to this thread.
Best, Chris
Please post your solutions to the Nov 10 In-Class Exercise to this thread.
Best,
Chris
2021-11-14
((resource:WhatsApp Image 2021-11-15 at 2.16.42 AM.jpeg|Resource Description for WhatsApp Image 2021-11-15 at 2.16.42 AM.jpeg))
((resource:WhatsApp Image 2021-11-15 at 2.13.02 AM.jpeg|Resource Description for WhatsApp Image 2021-11-15 at 2.13.02 AM.jpeg))
((resource:inclass rnn mod 8.jpg|Resource Description for inclass rnn mod 8.jpg))
((resource:Picture1.png|Resource Description for Picture1.png))
We want to produce an output that is a number modulo 8. These numbers are {0,1,2,3,4,5,6,7} which can be represented as 3-bit binary numbers.
- We will use 3 neurons where each neuron will represent the bits in the output.
- Every neuron will get 4 inputs (1 input bit from the sequence + 3 neuron outputs from the previous time step)
The following diagram will summarize the network.
Neurons are numbered 1 through 3 from top to bottom in the above diagram.
Neuron 1 will compute: (y_1)^t = (y_1)^(t-1) OR ((y_2)^(t-1) AND (x^t AND (y_3)^(t-1))
Neuron 2 will compute: (y_2)^t = (y_2)^(t-1) OR (x^t AND (y_3)^(t-1))
Neuron 3 will compute: (y_3)^t = (x^t OR (y_3)^(t-1))
We want to produce an output that is a number modulo 8.
These numbers are {0,1,2,3,4,5,6,7} which can be represented as 3-bit binary numbers.
* We will use 3 neurons where each neuron will represent the bits in the output.
* Every neuron will get 4 inputs (1 input bit from the sequence + 3 neuron outputs from the previous time step)
The following diagram will summarize the network.
((resource:Screen Shot 2021-11-15 at 10.13.27.png|Resource Description for Screen Shot 2021-11-15 at 10.13.27.png))
Neurons are numbered 1 through 3 from top to bottom in the above diagram.
Neuron 1 will compute: @BT@(y_1)^t = (y_1)^(t-1) OR ((y_2)^(t-1) AND (x^t AND (y_3)^(t-1))@BT@
Neuron 2 will compute: @BT@(y_2)^t = (y_2)^(t-1) OR (x^t AND (y_3)^(t-1))@BT@
Neuron 3 will compute: @BT@(y_3)^t = (x^t OR (y_3)^(t-1))@BT@
((resource:IMG_20211115_110544.jpg|Resource Description for IMG_20211115_110544.jpg))
((resource:WhatsApp Image 2021-11-15 at 1.45.03 PM.jpeg|Resource Description for WhatsApp Image 2021-11-15 at 1.45.03 PM.jpeg))
((resource:image_123927839.JPG|Resource Description for image_123927839.JPG))
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