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Dec 6 In-Class Exercise Thread.

Post your answers to the Dec. 6 In-Class Exercise to this thread.

Best, Chris

Post your answers to the Dec. 6 In-Class Exercise to this thread. Best, Chris

-- Dec 6 In-Class Exercise Thread

In the set, we have {0, pi/2, -pi/2, pi} Using the three nearest neighbors, {pi/2, pi/4, 0} -- breaking ties between 0 & 3pi/4 by choosing the point closest to the origin, 3pi/8 is in the set. (using euclidian distance)

Student: Naomi Campbell

(Edited: 2017-12-06)

In the set, we have {0, pi/2, -pi/2, pi} Using the three nearest neighbors, {pi/2, pi/4, 0} -- breaking ties between 0 & 3pi/4 by choosing the point closest to the origin, 3pi/8 is in the set. (using euclidian distance) ((resource:DSC_3673.JPG|Resource Description for DSC_3673.JPG)) Student: Naomi Campbell

-- Dec 6 In-Class Exercise Thread

Student: Wei Su

(Edited: 2017-12-06)

Student: Wei Su ((resource:20171207_040637869_iOS.jpg|Resource Description for 20171207_040637869_iOS.jpg))

-- Dec 6 In-Class Exercise Thread

((resource:IMG_9910.jpg|Resource Description for IMG_9910.jpg)) ((resource:IMG_9909.jpg|Resource Description for IMG_9909.jpg))

-- Dec 6 In-Class Exercise Thread

Xin Yan

((resource:WechatIMG15.jpeg|Resource Description for WechatIMG15.jpeg)) Xin Yan

-- Dec 6 In-Class Exercise Thread

Michael Torres

Michael Torres ---- ((resource:IMG_1115.JPG|Resource Description for IMG_1115.JPG))

-- Dec 6 In-Class Exercise Thread

((resource:IMG_0394.jpg|Resource Description for IMG_0394.jpg))

-- Dec 6 In-Class Exercise Thread

Student: Phyllis Lau

(Edited: 2017-12-07)

Student: Phyllis Lau ((resource:FullSizeRender.jpg|Resource Description for FullSizeRender.jpg))

-- Dec 6 In-Class Exercise Thread

((resource:50A13298-05F7-40A2-BF41-37E568174FC6.jpeg|Resource Description for 50A13298-05F7-40A2-BF41-37E568174FC6.jpeg))

-- Dec 6 In-Class Exercise Thread

                                      X=0
                                    /                                                                                \
                                   /                                                                                y=0
                                 y   =   0                                                                       /                                                                \
                                /                \                                                             x =-2^0.5/4                                        x = -2^0.5/2
                                                                                                                   /        \                                               /          \
              (-2^0.5/2, 2^0.5/2)    x= (-2-2^0.5)/4                                (0,-1)         (2^0.5/2,-2^0.5/2)           (0,1)            y = 2+2^0.5/4
                                                         /       \                                                                                                                       /     \
                                                  (1,0)       (-2^0.5/2,2^0.5/2)                                                                                      (1,0)      (2^0.5/2)

(Edited: 2017-12-13)

X=0 / \ / y=0 y = 0 / \ / \ x =-2^0.5/4 x = -2^0.5/2 / \ / \ (-2^0.5/2, 2^0.5/2) x= (-2-2^0.5)/4 (0,-1) (2^0.5/2,-2^0.5/2) (0,1) y = 2+2^0.5/4 / \ / \ (1,0) (-2^0.5/2,2^0.5/2) (1,0) (2^0.5/2)