2018-11-06

Nov 7 In-Class Exercise .

Post your solutions to the Nov 7 In-Class Exercise tot this thread.

Best,

Chris

Post your solutions to the Nov 7 In-Class Exercise tot this thread. Best, Chris
2018-11-07

-- Nov 7 In-Class Exercise

len(d) = 250, ftd = 2, number of times star appears in the corpus = 73695, words in corpus = 450000000, Mct = 73695/450000000 = 0.00016,

Mμd(t) = 2 + μ (0.00016)/250+μ,

μ=100, 2.016/350 = 0.006

μ=1000, 2.16/1250 = 0.0018

μ=10000, 3.6/10250 = 0.00034

ftd = 0, 4.) Mμd(t) = 0.16/1250 = 0.00013

(Edited: 2018-11-07)
len(d) = 250, ftd = 2, number of times star appears in the corpus = 73695, words in corpus = 450000000, Mct = 73695/450000000 = 0.00016, Mμd(t) = 2 + μ (0.00016)/250+μ, # μ=100, 2.016/350 = 0.006 # μ=1000, 2.16/1250 = 0.0018 # μ=10000, 3.6/10250 = 0.00034 ftd = 0, 4.) Mμd(t) = 0.16/1250 = 0.00013

-- Nov 7 In-Class Exercise

when u = 100, M_u_d (t) = (2 + 100 * ( 73695/450000000) ) / (250 + 100) = 0.005 when u = 1000, M_u_d (t) = (2 + 1000 * ( 73695/450000000) ) / (250 + 1000) = 0.0017 when u = 10000, M_u_d (t) = (2 + 10000* ( 73695/450000000) ) / (250 + 10000) = 0.00035

if star does not appear in d, u = 1000, M_u_d = (1000 * ( 73695/450000000) ) / (250 + 1000) = 0.00013

(Edited: 2018-11-07)
when u = 100, M_u_d (t) = (2 + 100 * ( 73695/450000000) ) / (250 + 100) = 0.005 when u = 1000, M_u_d (t) = (2 + 1000 * ( 73695/450000000) ) / (250 + 1000) = 0.0017 when u = 10000, M_u_d (t) = (2 + 10000* ( 73695/450000000) ) / (250 + 10000) = 0.00035 if star does not appear in d, u = 1000, M_u_d = (1000 * ( 73695/450000000) ) / (250 + 1000) = 0.00013

-- Nov 7 In-Class Exercise

M_d^(\mu) (t) = (2 + (73695/450000000) * \mu) / (250 + \mu)

\mu = 100, M_d^(\mu) (t) = 0.5761%

\mu = 1000, M_d^(\mu) (t) = 0.1731%

\mu = 10000, M_d^(\mu) (t) = 0.0355%

Where star does not appear in d and \mu = 1000:

M_d^(\mu) (t) = 0.0131%

(Edited: 2018-11-07)
@BT@M_d^(\mu) (t) = (2 + (73695/450000000) * \mu) / (250 + \mu)@BT@ @BT@\mu = 100, M_d^(\mu) (t) = 0.5761%@BT@ @BT@\mu = 1000, M_d^(\mu) (t) = 0.1731%@BT@ @BT@\mu = 10000, M_d^(\mu) (t) = 0.0355%@BT@ Where star does not appear in @BT@d@BT@ and @BT@\mu = 1000@BT@: @BT@M_d^(\mu) (t) = 0.0131%@BT@

-- Nov 7 In-Class Exercise

a)M_d^mu(t) = (2 + 100(73695 / 450000000)) / (250+100) = 0.0058

b)M_d^mu(t) = (2 + 1000(73695 / 450000000)) / (250+1000) = 0.0017

c)M_d^mu(t) = (2 + 10000(73695 / 450000000)) / (250+10000) = 0.0004

d)M_d^mu(t) = (0 + 1000(73695 / 450000000)) / (250+1000) = 0.0001

(Edited: 2018-11-07)
a)@BT@M_d^mu(t)@BT@ = (2 + 100(73695 / 450000000)) / (250+100) = 0.0058 b)@BT@M_d^mu(t)@BT@ = (2 + 1000(73695 / 450000000)) / (250+1000) = 0.0017 c)@BT@M_d^mu(t)@BT@ = (2 + 10000(73695 / 450000000)) / (250+10000) = 0.0004 d)@BT@M_d^mu(t)@BT@ = (0 + 1000(73695 / 450000000)) / (250+1000) = 0.0001

-- Nov 7 In-Class Exercise
  1. mu= 100

M_d^100(mbox{star}) = 2+(100*0.00016)/350 = 2.016/350 = 0.005761

  1. mu= 1000

M_d^1000(mbox{star}) = 2+(1000*0.00016)/1250 = 2.1637/1250 = 0.0017

  1. mu= 10000

M_d^10000(mbox{star}) = 2+(10000*0.00016)/10250 = 3.6/10250 = 0.00035

If star doesn't appear in d

M_d^1000(mbox{star}) = 0+(1000*0.00016)/1248 = 0.000128

(Edited: 2018-11-07)
1. @BT@mu@BT@= 100 @BT@M_d^100(mbox{star}) = 2+(100*0.00016)/350 = 2.016/350 = 0.005761@BT@ 2. @BT@mu@BT@= 1000 @BT@M_d^1000(mbox{star}) = 2+(1000*0.00016)/1250 = 2.1637/1250 = 0.0017@BT@ 3. @BT@mu@BT@= 10000 @BT@M_d^10000(mbox{star}) = 2+(10000*0.00016)/10250 = 3.6/10250 = 0.00035@BT@ If star doesn't appear in d @BT@M_d^1000(mbox{star}) = 0+(1000*0.00016)/1248 = 0.000128@BT@

-- Nov 7 In-Class Exercise

M_C("star") = l_t/l_C

M_C("star") = 73695 / 450000000

M_C("star") = 0.000163767

(a) mu = 100

#M_d^100("star") = (2 + (100 * 0.000163767))/(250 + 100) #M_d^100("star") = 0.005761076

(b) mu = 1000

#M_d^1000("star") = (2 + (1000 * 0.000163767))/(250 + 1000) #M_d^1000("star") = 0.001731014

(c) mu = 10000

#M_d^10000("star") = (2 + (10000 * 0.000163767))/(250 + 10000) #M_d^10000("star") = 0.000354895

(d) mu = 1000 and f_(t,d) = 0

#M_d^1000("star") = (0 + (1000 * 0.000163767))/(250 + 1000) #M_d^1000("star") = 0.000131014

(Edited: 2018-11-07)
@BT@M_C("star") = l_t/l_C@BT@ @BT@M_C("star") = 73695 / 450000000@BT@ @BT@M_C("star") = 0.000163767@BT@ (a) @BT@mu = 100@BT@ #@BT@M_d^100("star") = (2 + (100 * 0.000163767))/(250 + 100)@BT@ #@BT@M_d^100("star") = 0.005761076@BT@ (b) @BT@mu = 1000@BT@ #@BT@M_d^1000("star") = (2 + (1000 * 0.000163767))/(250 + 1000)@BT@ #@BT@M_d^1000("star") = 0.001731014@BT@ (c) @BT@mu = 10000@BT@ #@BT@M_d^10000("star") = (2 + (10000 * 0.000163767))/(250 + 10000)@BT@ #@BT@M_d^10000("star") = 0.000354895@BT@ (d) @BT@mu = 1000 and f_(t,d) = 0@BT@ #@BT@M_d^1000("star") = (0 + (1000 * 0.000163767))/(250 + 1000)@BT@ #@BT@M_d^1000("star") = 0.000131014@BT@

-- Nov 7 In-Class Exercise

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-- Nov 7 In-Class Exercise

<pre>

a) μ = 100; = (f + μ⋅MC(t))/ (ld+μ) = (2+100.(73695/45010^6))/(250+100) = 2.0164/350 = '''0.00576''' b) mu = 1000 => (2+(73695/45010^3))/250+1000 = 2.1637/1250 =''' 0.00173''' c) mu= 10000 => (2+(73695/450*10^2))/250+10000 = 3.637/10250 = '''0.00035'''

  1. without 'star'

0+(73695/450*10^3)/250+1000 => 0.0164/1250 = '''0.000013'''

</pre>

(Edited: 2018-11-12)
<pre> 1. a) μ = 100; = (f + μ⋅MC(t))/ (ld+μ) = (2+100.(73695/450*10^6))/(250+100) = 2.0164/350 = '''0.00576''' b) mu = 1000 => (2+(73695/450*10^3))/250+1000 = 2.1637/1250 =''' 0.00173''' c) mu= 10000 => (2+(73695/450*10^2))/250+10000 = 3.637/10250 = '''0.00035''' 2. without 'star' 0+(73695/450*10^3)/250+1000 => 0.0164/1250 = '''0.000013''' </pre>

-- Nov 7 In-Class Exercise

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